The equilibrium constants for the reaction Br2 =2 Br at 500K and 700 K are 10^-10 and 10^-5. The reaction is? Answer is endothermic but in the option one is slow but given incorrect. Why isn't the reaction slow?

Br2 2 BrKC = [Br]2[Br2] Kc at 500K and 700k are 1×10-10 and 1×10-5 and it indicates that the formation of Br is favoured with increase in temperature. So the reaction is endothermic.With the increae in temperature, the decomposiition is favoured, soits not a slow reaction. 

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