The equilibrium constants for the reaction Br2 =2 Br at 500K and 700 K are 10^-10 and 10^-5. The reaction is? Answer is endothermic but in the option one is slow but given incorrect. Why isn't the reaction slow? Share with your friends Share 10 Geetha answered this Br2 ↔2 BrKC = [Br]2[Br2] Kc at 500K and 700k are 1×10-10 and 1×10-5 and it indicates that the formation of Br is favoured with increase in temperature. So the reaction is endothermic.With the increae in temperature, the decomposiition is favoured, soits not a slow reaction. 17 View Full Answer