The expression [tan (x- pi/2) cos(3pi/2 + x)] - [sin37pi/2-x] / [cos(x-pi/2)tan(3pi/2 + x)] simplifies to 1+cos2x sin2x - Maths - Trigonometric Functions

Question

The expression [tan (x- pi/2) cos(3pi/2 + x)] -
[sin​37pi/2-x] / [cos(x-pi/2)tan(3pi/2 + x)]
simplifies to

1+cos2x
sin2x
-(1+cos2x)
cos2x

Brijendra Pal · Accepted Answer

The expression [tan (x- pi/2).cos(3pi/2 + x)] - [sin​37pi/2-x] / [cos(x-pi/2)tan(3pi/2 + x)] simplifies to 1+cos2x sin2x -(1+cos2x) cos2x