The given figure shows a right angled triangle ABC and an equilateral triangle BCD. Find the area of the shaded portion. (Given : AC = 16 cm, BC = 8 cm )​​

AC2=AB2+BC2
AB=sq. root of AC2-BC2
     =sq. root of (16)2-(8)2
     =sq. root of 256-64
     =sq. root of 192
     =13.86 cm (approx)
area of triangle ABC
=(1/2)*BC*AB
=(1/2)*8*13.86
=4*13.86
=55.44 cm2
area of triangle equilateral BCD
=(root3 /4)*(BC)2
=(root3 /4)*8*8
=16 root 3
=16*1.732
=27.712 cm2
area of shaded portion
=55.44-27.712
=27.728 cm2
     
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