The given figure shows a simple circuit diagram. If the 6 ohm resistor is removed from the circuit,then the currents flowing through the 8 ohm and 2 ohm resistors would
A) increase in both cases
B) decrease in both cases
C) increase and decrease respectively
D) decrease and increase respectively

Dear Student,Let,V=12VThe total resistance of the circuit when 6Ω resistor is present is,R1=6×86+8+2=4814+2=3.42+2=5.42Ω Main current in the circuit is,I=VR1=125.42=2.21AThis current flows through 2Ω resistor.Therefore,I2=2.21AVoltage drop across parallel combination is,Vd=12-2.21×2=7.58VCurrent through  8Ω resistor is,I8=VdR=7.588=0.947ANow, when the 6Ω resistor is removed total resistance of the circuit is,R2=8+2=10ΩMain current in the circuit is,I=VR2=1210=1.2AAs they are in series, this main current flows through both 8Ω and 2Ω  resistors.Therefore,I2'= I8'=1.2AHere,I8'>I8  and I2' <I2Ans: c)increases and decreases respectively.Regards.

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really sry, no idea
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