The Indian High SchoolSummer AssignmentRevision Term 1Grade:9Answer as many as possible:1) State universal law of gravitation. Express it mathematically.2) Differentiate between G and g in tabular form.3) (a) What is acceleration ? Write its unit.(b) Draw velocity-time graph, when an object has (i) uniformly accelerated velocity.(ii) uniformly retarded velocity.4) Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent.5) The earth attracts the moon. Does the moon also attract the earth ? If it does, why does the earth not move towards the moon ?6) A bullet of mass 10 g is fired with a velocity of 400 m/s from a gun of mass 4 kg. What is the recoil velocity of the gun ?7) What is weight ? State the direction in which it acts. Write an expression for it. Is the weight of an object same on the earth and the moon ? Why ?8) A circular track has a circumference of 1570 m with AB as one of its diameter. A scooterist moves from A to B along the circular path with a uniform speed of 5 m/s. Find the :(a) distance covered by the scooterist, (b) displacement of the scooterist (Given Π=3.14),(c) time taken by the scooterist in reaching from A to B.9) A man throws a ball of mass 0.5 kg vertically upward with a velocity of 25 m/s. Find : (a) the initial momentum of the ball (b) momentum of the ball at the half way mark of the maximum height (given g=10 m/s2)10) A body thrown in the vertically upward direction rises upto a height h‟ and comes back to the position of its start. Calculate (a) the total distance travelled by the body and (b) the displacement of the body.Under what condition will the magnitude of the displacement be equal to the distance travelled by an object ?11) Which is having a higher value of momentum - A bullet of mass 10 g moving with a velocity of 400m/s or a cricket ball of mass 400g thrown with the speed of 90 km/h ?12)Show that weight of an object on the moon is 1/6 of its weight on the earth. [Given : mass of earth = 5.98*1024 kg, mass of moon = 7.36*1022 kg, radius of earth = 6.37*106 m, radius of moon =1.74*106 m]13) A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40,000 N and the track offers a friction force of 5,000 N then calculate : (a) the net accelerating force. (b) the acceleration of the train. (c) the force of the wagon 1 on rest of the wagons.14) A stone is allowed to fall from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 ms-1. Calculate when and where the two stones will meet ? (Take g = 10ms-2)15) The velocitytime graph of a car is given below. The car weighs 1000 kg. (i) What is the distance travelled by the car in the first 2 seconds ? (ii) What is the braking force at the end of 5 seconds to bring the car to a stop within one second ?16) State universal law of gravitation. How the force between the two bodies is affected 2 if the distance between them is tripled ?17) Define acceleration. State a relationship connecting u, v, a and t for an accelerated motion. Give an example of a motion in which acceleration is uniform.18) (a) Name the property by virtue of which a body resists a change in its state of motion. Name the physical quantity which is a measure of this property. (b) Explain why some of the leaves may get detached from a tree if we vigorously shake its branch.19) A man throws a ball of mass 0.5 kg vertically upward with a velocity of 25 m/s. Find : (a) the initial momentum of the ball (b) momentum of the ball at the half way mark of the maximum height (given g=10 m/s2)20) A stone of mass 1 kg is thrown with a velocity 20 m/s across the frozen surface of a lake and comes to rest after travelling a distance of 50 m. What is the force of friction between the stone and ice ?

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Answer 1-

Universal law of gravitation 

The universal law of gravitation states that there is a force of attraction between two masses separated by some distance. The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Mathematically,

Where, G is the universal gravitational constant and G=6.67 x 10-11 Nm2/kg2

m1 and m1 are the masses separated by a distance r.

The Universal Law of Gravitation is applied in the study of motion of objects in the presence of gravitational field. Motion of astronomical bodies are calculated and also predicted using this law.

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1) the universal law states that the law of gravitation states that the force of attraction between any two objects is proportional to to the product of their masses and inversely proportional to the square of the distance between them. this law is applied every where in the universe.(G=F*d2/M1*M2)

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