The interference fringes for sodium light of wavelength 5980angstrom in a double slit experiment have an angular width of 0.20degree . For what wavelength will this width be 10% greater. Share with your friends Share 8 Gurpreet K. answered this Dear Student, Angular width of fringes in an interference pattern is given by θ=λd⇒θ∝λNew angular width θ'=θ+10100θ=1.1θ∴θ'θ=λ'λ⇒λ'=1.1×λ=1.1×5980 A˙⇒λ'=6578 A˙ 14 View Full Answer