The interference fringes for sodium light of wavelength 5980angstrom in a double slit experiment have an angular width of 0.20degree . For what wavelength will this width be 10% greater.

Dear Student,


Angular width of fringes in an interference pattern is given by

θ=λdθλNew angular width θ'=θ+10100θ=1.1θθ'θ=λ'λλ'=1.1×λ=1.1×5980 A˙λ'=6578 A˙

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