The kinetic energy of a car is 7000 J as it travels along a horizontal road. How much work is required to stop the car in 20 s?

Work done, W = (K.E.)f - (K.E.)i

= 0 - 7000

= -7000 J

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350 jouels is the correct answer
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A car travels with a kinetic energy of 7000 J as it travels along a horizontal road how much work is required to stop the car?
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The amount of work required, assuming that the brakes work at 100% efficiency is ... 7000 Joules.

 

The brakes transform the car's kinetic energy into heat energy. The rate (power) for this is 7000/20 Joules/second = 350 J/s

 

But wait! The proper unit for Joules/second is Watts. So the brakes dissipate the car's energy into heat as a rate of 350 Watts.

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 WORK DONE TO STOP= K.E f - K.Ei = -7000J
POWER= -7000/20= 350W
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