the line x/a + y/b = 1 moves in such a way that 1/a2 +1/b2 = 1/c2 , where c - Maths - Straight Lines

Question

the line x/a + y/b = 1 moves in such a way that 1/a2
+1/b2 = 1/c2 , where c is a constant the
locus of the foot of the perpendicular from the origin on the given
line is x2+ y2= c2

Anuradha Sharma · Accepted Answer

the line x/a + y/b = 1 moves in such a way that 1/a2 +1/b2 = 1/c2 , where c is a constant. the locus of the foot of the perpendicular from the origin on the given line is x2+ y2= c2.

the line x/a + y/b = 1 moves in such a way that 1/a² +1/b² = 1/c² , where c is a constant. the locus of the foot of the perpendicular from the origin on the given line is x²+ y²= c^2.