The locus of centre of a circle of radius 2 which rolls on the outside of the circle x^2+y^2+3x-6y-9=0 is (a)x^2+y^2+3x-6y+5=0 (b)x^2+y^2+3x-6y-31=0 (c)x^2+y^2+3x-6y+29/4=0 (d)x^2+y^2+3x-6y-5=0 Share with your friends Share 25 Lovina Kansal answered this Dear student Let (h,k) be the centre of the circle which rolls on the outside of the given circle.Centre of the given circle is (-3/2,3) and its radius=94+9+9=92Clearly, 9h,k) is always at a distance equal to the sum 92+2=132 of the radii of two circlefrom -32,3.Therefore,h+322+k-32=1322⇒h2+k2+3h-6k+94+9-1694=0Hence locus of h,k is x2+y2+3x-6y-31=0 Regards 59 View Full Answer
