↵The mean and variance of a binomial distribution is 4 and 4/3 resp. Find the distribution P(X>=1) Share with your friends Share 3 Varun.Rawat answered this We have,mean = np = 4 .....1variance = npq = 43 .....2Substituting the value of np from 1 in 2, we get⇒4q = 43⇒q = 13Now, p = 1 - q = 1-13 = 23Now, np = 4⇒2n3 = 4⇒n = 6So, binomial distribution is,PX=r = Crn pr qn-r = Cr6 23r 136-rNow, PX⩾1 = 1-PX=0 = 1 - C06 230 136-0 = 1 - 1729 = 728729 25 View Full Answer Lalitha answered this np=4npq=4/3q=1/3p=2/3n=6reqd P=1-P(x=0) = 1-64/249 = 185/249 -5