↵The mean and variance of a binomial distribution is 4 and 4/3 resp. Find the distribution P(X>=1)

We have,mean = np = 4   .....1variance = npq = 43    .....2Substituting the value of np from 1 in 2, we get4q = 43q = 13Now, p = 1 - q = 1-13 = 23Now, np = 42n3 = 4n = 6So, binomial distribution is,PX=r = Crn pr qn-r = Cr6 23r 136-rNow, PX1 = 1-PX=0 = 1 - C06 230 136-0 = 1 - 1729 = 728729

  • 25
np=4
npq=4/3
q=1/3
p=2/3
n=6
reqd P=1-P(x=0) = 1-64/249 = 185/249
 
  • -5
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