The mean of three numbers is 40. All the three numbers are different natural numbers. If lowest is 19, what coould be the highest possible number of remaining twonumbers.

Answer : 

Given  : The mean of three number  =  40 

And 

two numbers  =  x and y and given third number ( lowest of these three numbers  ) = 19  

So, 

x +y +193 = 40x +y +19 = 120x +y  = 101
we get second highest number in order to get highest possible number  =  20 

SO, 

Highest possible number  =  101 - 20 = 81                              ( Ans )

  • 8
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