The molality of a solution of KCl (molar mass = 74.5 g mol−1) in water is 3 m.
What is the mass percent of KCl in the solution?
Answer me as soon as possible
probably this is right......
molality = 3 , this means that there are 3 moles of KCl in 1000 g of solvent(water).
3 moles of KCl = 3*74.5 = 223.5 g of KCl
mass of solution = 1000g + 223.5g =1223.5g
thus % of KCl=( 223.5 / 1223.5 ) x 100 =18.26 %