The number of free electrons per 10mm of an ordinary copper wire is 2*10^21.
The average drift speed of the electron is 0.25mm/s.The current flowing is:
(a)0.8 A (b)8A
(c) 80 A (d)5A
(e) 0.5A
I=jA
according to the relation between the drift speed and current density, we get
I= neAvd
putting n=2*10^21, e=1.6*10^-19 , A= 10^2 and vd= 2.5*10^-4 we get
I = 8 amperes.
according to the relation between the drift speed and current density, we get
I= neAvd
putting n=2*10^21, e=1.6*10^-19 , A= 10^2 and vd= 2.5*10^-4 we get
I = 8 amperes.
