THE PERIMETER OF A SECTOR OF A CIRCLE WITH CENTRAL ANGLE 90* IS 25CM FIND THE AREA OF THE MINOR SEGMENT OF THE CIRCLE.
Let r be the radius of a sector of a circle with center at O.
Length of the arc ACB = l = θ / 3600 × 2 π r = 900 / 3600 × 2 × 22 / 7 × r = 11r / 7 cm
perimeter of the sector AOBCA = 25 cm
r + r + l = 25 ⇒ 2r + 11r / 7 = 25 ⇒ r = 7 cm
area of the minor segment ABCA = Area of the sector AOBCA - area of Δ AOB