the perimeter of a triangular field is 300cm.and its sides are in the ratio 5:12:13.find the length of the perpendicular from the opposite vertex to the side whose length is 130cm?

Perimeter=300cm
Sides are 5x, 12x, 13x 
5x+12x+13x=300
30x=300
x=300/30
x=10
 
First Side=5x=50
Second Side=12x=120
Third Side=13x=130
 s= (50+120+130)/2 =150 (“s” is the semi perimeter)
According to Heron’s Formula [A=√s(s-a)(s-b)(s-c)],
Area=√ 150(150-50)(150-120)(150-130)
         =√150*100*30*20
         =3*10*10
         =300
Area=1/2 bh
 300 =1/2*130*h
 300 =65h
 h     =300/65
 h     =6.62cm (approx)
 

  • 2

tnx Nishanth!

  • -2
The Area is not 300. It is 3000 cm^2. 
So,
Area=1/2 bh
3000=1/2*130*h 
h= 3000*2/130
h= 46.15 cm
  • 13
shania is correct 
 
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The  perimeter  of a triangular field is 144m and its sides are in the ratio 3:4:5 .Find the length of the perpendicular from the opposite vertex to the longest side.                                                              
  • -1
The perimeter of a triangular field is 300m and its sides are in the ratio 5:12:13. Find the length of the perpendicular from opposite vertex to the greatest side.
  • 1
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