the population of a city decreased by5% due to earthquake. if now it is 190000, what was it before the earthquake?

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Please find below the solution to the asked query :

$$\begin{gathered} \mathrm{Let} \mathrm{the} \mathrm{population} \mathrm{before} \mathrm{earthquake} \mathrm{be} \mathrm{x} . \\ \mathrm{A}.\mathrm{T}.\mathrm{Q} \\ \mathrm{x} - 5 \% \mathrm{of} \mathrm{x} =190000 \\ \mathrm{x}-\frac{5}{100}\times \mathrm{x}=190000 \\ \frac{100\mathrm{x}-5\mathrm{x}}{100}=190000 \\ \frac{95\mathrm{x}}{100}=190000 \\ 95\mathrm{x}=190000\times 100 \\ \mathrm{x}=\frac{190000\times 100}{95} \\ =2000\times 100 \\ =200000 \mathrm{ANS}... \end{gathered}$$

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