The potential difference between the plates of a parallel plate capacitors is 200 V.The area of each plate is 100 cm^2 and the distance between them is 1mm.If the medium between them is air,then calculate the charge taken by the capacitor.If there is a medium of dielectric Constant 2.5 between the plates,then what will be the potential difference for the same charge???
Answer-1.76?10^-8 C or 80V

The potential difference between the plates of parallel plate capacitor
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Given V=200V A=100cm^2=100×10^-4m^2 1mm=1×10^-3 C=abssylon zeroA÷d =(8.85×10^-12)(0.01)÷(1×10^-3) =8.85×10^-11 C=Q÷V =8.85×10^-11×200 =1.77×10^-8
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