The potential difference between the terminals of a battery of emf = 10 V and internal resistance 1 Ohm drops to 9.8 V when connected accross an external resistance. The resistance of the external resistor is
(A) 49 Ohm
(B) 25 Ohm
(C) 31 Ohm
(D) 43 Ohm
Answer is A)49 Ohm
Because Voltage across the internal resistor is 10-9.8=0.2V
Current through the circuit is 0.2/1 =0.2 Amperes.
Voltage across the External resistor is 9.8V
Resistance of External Resistor is = 9.8/0.2 =49 Ohm.
I think You understand.