The radius of the nearly circular orbit of mercury is5.8 X 10^10m and its orbital period is 88 days. If a hypothetical planet has an orbital period of 55 days what is the radius of its circular orbit?

From Kepler's law of orbits,T2 α R3T23α RR α T23R2R1=T2T123R2=R1T2T123     =5.8×1010558823     =4.24×1010 days

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