The radius of the nearly circular orbit of mercury is5.8 X 10^10m and its orbital period is 88 days. If a hypothetical planet has an orbital period of 55 days what is the radius of its circular orbit? Share with your friends Share 11 Vara answered this From Kepler's law of orbits,T2 α R3T23α RR α T23R2R1=T2T123R2=R1T2T123 =5.8×1010558823 =4.24×1010 days 44 View Full Answer