the refracting angle of a glass prism of refractive index 1.45 is 60 degrees. At what angle should a light ray be incident at the first face of the at prism so that it emerges at the second face just parallel to the face??

Given,
ng=1.45A=600i=?e=900In this case,r2=C (Critical angle)sin C=1ng=sin r2=11.45----(i)Also,sin isin r1=ng=1.45Thus, sin i=1.45×sin r1But r1+r2=A=600or r1=600-r2Thus,sin i=1.45×sin (600-r2)Expanding the above and using (i), we geti=sin-1[1.45×sin6001-11.452-cos 600]=sin-1(0.4)

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