The roots alpha and beta of the quadratic equation x2-5x +3(k-1) = 0 are such that alpha - beta= 11 . Find the value of k

Given
α-β=11...(1)Since α and β are roots of x2-5x+3(k-1)=0,sum of roots=-ba=-(-5)1=5So, α+β=5 ...(2)(1)+(2) gives,2α=16α=8Since α=8 is a root, it will satisfy the given equation.So,82-5(8)+3(k-1)=064-40+3k-3=03k=-21k=-7

  • 27

alpha and bihta

  • -10

alpha and bihta

  • -5
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