The square of side 12 cm is cut on the diagonals find the perimeter of One triangle so formed
By Pythagoras Theorem:
The length of third side of the triangle
= (122 + 122)1/2
= 12*(2)1/2 cm.
Hence, the perimeter of the triangles so formed is:
= 12 + 12 + 12*(2)1/2 cm
= 12* [ 2 + (2)1/2 ] cm
= 12*(2)1/2 * [(2)1/2 + 1] cm
The length of third side of the triangle
= (122 + 122)1/2
= 12*(2)1/2 cm.
Hence, the perimeter of the triangles so formed is:
= 12 + 12 + 12*(2)1/2 cm
= 12* [ 2 + (2)1/2 ] cm
= 12*(2)1/2 * [(2)1/2 + 1] cm