The taxi in a city are as follows:Rs 15 for first kilometer and Rs 8 for every subsequent kilometer.Taking the total distance covered as x and total fare as y,write the above as a linear equation.
Dear user,
Here is the answer to your question.
It can be observed that
Taxi fare for 1st km = 20
Taxi fare for first 2 km = 20 + 9 = 29
Taxi fare for first 3 km = 29 + 9 = 38
Taxi fare for first 4 km = 38 + 9 = 46
Clearly 20, 29, 38, 46 … forms an A.P. because every term is 9 more than the preceding term.
Let a and d respectively be the first term and common difference of A.P.
Taxi fare for first x km = xth term of the A.P.
y = a + (x – 1)d
y = 20 + (x – 1)9
y = 20 + 9x – 9
y = 9x + 11
All the Best!