The taxi in a city are as follows:Rs 15 for first kilometer and Rs 8 for every subsequent kilometer.Taking the total distance covered as x and total fare as y,write the above as a linear equation.

Dear user,

Here is the answer to your question.

 

It can be observed that

Taxi fare for 1st km = 20

Taxi fare for first 2 km = 20 + 9 = 29

Taxi fare for first 3 km = 29 + 9 = 38

Taxi fare for first 4 km = 38 + 9 = 46

Clearly 20, 29, 38, 46 … forms an A.P. because every term is 9 more than the preceding term.

Let a and d respectively be the first term and common difference of A.P.

Taxi fare for first x km = xth term of the A.P.

y = a + (x – 1)d

y = 20 + (x – 1)9

y = 20 + 9x – 9

y = 9x + 11

 

All the Best!

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