The time period of a mass loaded spring is 'T' . If 20% of its turns are cut and removed, then with what time period the same mass attached to the remaining spring would oscillate? Share with your friends Share 3 Sanjay Singh answered this Dear student We know that time period of spring mass system is T=2πmk ....1 ( m is mass of block and k is spring constant) Let length of spring is L.When the length is cut by 20 percent than length of remaining spring is (L-L5)=4L5Spring constant is inversely proportional to natural length ofspring so product of spring constant and length of spring is constant. K×L=constantK×L=K1×4L5 (K1 is spring constant of spring after it is cut)K1=5K4so time period isT1=2πmK1=2π4m5KT1=2πmK (25).....2comparing eqn ...2 with eqn ...1T1=T (25)Regards 9 View Full Answer Anonymous A2z answered this T/2 -1