The volume of CO, obtained at N T P by heating 200 g of 75% pure CaCO3 is (A) - Chemistry - Mole Concept and Stoichiometry

Question

The volume of CO, obtained at N T P by heating 200 g of 75% pure
CaCO3 is

(A) 88mL (B) 66mL (C) 33 6mL (D) 33 6L

Goutam Pradhan · Accepted Answer

Dear Student,
We have to find the volume of CO2 obtained at N T P by
heating 200g 75% pure CaCO3
The reaction is
CaCO3 →∆ CaO + CO2 Amount of pure CaCO3= 75% of 200g=75100×200=150g150g CaCO3=150g100gmol-1=1
5molAccording to the balanced equation,1 mol CaCO3 gives 1 mol CO21
5 mol CaCO3 gives 1 5 mol CO2 =1
5mol x 22 4 lmol-1=33
6L[1 mol gas at N T P = 22
4L]Option D is correctRegards

The volume of CO, obtained at N.T.P by heating 200 g of 75% pure CaCO3 is (A) 88mL (B) 66mL (C) 33.6mL (D) 33.6L

The volume of CO, obtained at N.T.P by heating 200 g of 75% pure CaCO3 is

(A) 88mL (B) 66mL (C) 33.6mL (D) 33.6L