The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl to give FeCl2 is?

Ans 1.2 kcal

The reaction involved is:

Fe +2HCl ---------->FeCl2  +H2

Work done = P(V2-V1)

Since mole of Fe used =112/56 =2

The moles of H2 formed =2

P*(VH2-Vi) = P*VH2

As Vi =0

For H2  P* VH2 = nRT

VH2 = nRT/P

W =P*nRT/P = nRT = 2*2*300=1200 cal or 1.2 kcal

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