Themeasures of two adjacent angles of a parallelogram are in the ratio3:2. Find the measure of each of the angles of the parallelogram.

Let themeasures of two adjacent angles, ∠Aand ∠B, of parallelogramABCD are in the ratio of 3:2. Let ∠A= 3x and ∠B = 2x

We knowthat the sum of the measures of adjacent angles is 180º for aparallelogram.

∠A+ ∠B = 180º

3x+ 2x = 180º

5x= 180º

∠A= ∠C = 3x = 108º (Opposite angles)

∠B= ∠D = 2x =72º (Opposite angles)

Thus, themeasures of the angles of the parallelogram are 108º, 72º,108º, and 72º.

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