Themeasures of two adjacent angles of a parallelogram are in the ratio3:2. Find the measure of each of the angles of the parallelogram.
Let themeasures of two adjacent angles, ∠Aand ∠B, of parallelogramABCD are in the ratio of 3:2. Let ∠A= 3x and ∠B = 2x
We knowthat the sum of the measures of adjacent angles is 180º for aparallelogram.
∠A+ ∠B = 180º
3x+ 2x = 180º
5x= 180º
∠A= ∠C = 3x = 108º (Opposite angles)
∠B= ∠D = 2x =72º (Opposite angles)
Thus, themeasures of the angles of the parallelogram are 108º, 72º,108º, and 72º.