There is question in Chapter test on Data Handling (Maths, CBSE, Class VII) : Find two numbers lying between the - Maths - Data Handling

Question

There is question in Chapter test on Data Handling (Maths,
CBSE, Class VII) :
Find two numbers lying between the mean of 3 and 6
and the mean of 1/2 & 1/5 It should be any number between 0 35
(7/20) & 4 5(9/2)i e may be 1 &2 But Meritnation
hascomputed mean of 7/20 & 9/2 which is 97/40 Again computed
mean of 97/40 & 7/20 which is 111/80 Final answer as per
Meritnation is 97/40 & 111/80
Request to clarify

Manmeet Singh · Accepted Answer

Mean of 3 and 6 =

Mean of

Now, we have to find 2 numbers lying between

$\frac{9}{2}, x, y, \frac{7}{20}$ We know that the mean of 2 numbers always lies between the two numbers So, the value of x = mean of

Thus, we have $\frac{9}{2}, \frac{97}{40}, y, \frac{7}{20}$ Now, to determine the value of y, Mean of

So, $y = \frac{111}{80}$

Thus, the required two numbers are

Hope, this clears your doubt