three coins are tossed together.find the probability of getting-a)exactly two heads b)at least two heads c)no head d)at least one head and one tail.

Dear student
Let S be the sample space.ThenS=HHH,HHT,HTH,THH,HTT,THT,TTH,TTTa)Let E=Event of getting exactly two heads. Then E=HHT,HTH,THHP(E)=ES=38b)Let F=Event of getting atleast two heads. Then F=HHH,HHT,HTH,THHP(F)=FS=48=12c) Let G=Event of getting no head. Then G=TTTP(G)=GS=18d) Let H=Event of getting atleast one head and one tail. Then H=HHT,HTH,THH,HTT,THT,TTHP(H)=HS=68=34
Regards

  • 28
h means heads, t means tails---- (HHH,HTH,HTT,TTT,THT,THH)
  • 9
a)2/6
b)2/6
c)3/6
d)3/6
  • -13
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