Three particles having their masses in the ratio 1:3:5 are kept at the vertices of a triangle ABC. Coordinates of A,B and C are (9,-3),(3,4) and (0,0). Find the coordinates of the centre of mass.

Hi, Here m1=x , m2= 3x , m3= 5 x and coordinates are 9,-3 = x1, y13,4= x2,y20,0= x3,y3so coordinates of center of mass = m1x1+m2x2+m3x3m1+m2+m3,m1y1+m2y2+m3y3m1+m2+m3=9x+9x+09x,-3x+12x+09x=2,1

  • 2
What are you looking for?