three students appear at an examination of math the probability of their success are 1/3,1/4,1/5 respectively the probability of success - Maths - Probability

Question

three students appear at an examination of math the probability of
their success are 1/3,1/4,1/5 respectively the probability of
success of at least two is ????

Ashwini Kumar · Accepted Answer

Let the three events A, B and C represents the success of three students
PA=13 ⇒PA' = 1 - PA = 1 - 13 = 23PB=14⇒PB' = 1 - PB = 1 - 14 = 34PC=15⇒PC' = 1 - PC=1 - 15 = 45Required probability = PABC' + PAB'C + PA'BC + PABC=PA
PB PC' + PA PB' PC + PA' PB PC + PA
PB
PC=13×14×45 + 13×34×15 + 23×14×15+13×14×15 =1060 = 16

three students appear at an examination of math.the probability of their success are 1/3,1/4,1/5 respectively.the probability of success of at least two is ..????