To deposit one gm equivalent of an element at an electrode, the quantity of electric charges needed are?

Dear Student,

Gram equivalent of any element is an amount of element (in grams) that will release or react with an Avogadro's number of electrical charges on particles like OH^1-, H¹⁺ or electrons.

Electric charge on an electron is, $e=1.6\times {10}^{-19} \mathrm{C}$
Charge required to deposit one gram equivalent of an element at an electrode is,
$$\begin{gathered} Q=N_A\times e \\ \Rightarrow Q=6.022\times {10}^{23}\times 1.6\times {10}^{-19} \\ \Rightarrow Q=9.64\times {10}^4 \mathrm{C} \end{gathered}$$

Regards,