To obtain a number divisible by both 36 and 63 by which smallest number should 21 be multiplied Share with your friends Share 0 Abhishek Jha answered this Dear Student, the number divisible by both 36 and 63 is the LCM of 36 and 63.36=2×2×3×363=3×3×7so, LCM of 36 and 63=2×2×3×3×7=252So the required number by which 21 should be multiplied=25221=12 Regards 0 View Full Answer