To obtain a number divisible by both 36 and 63 by which smallest number should 21 be multiplied

Dear Student,
the number divisible by both 36 and 63 is the LCM  of 36 and 63.36=2×2×3×363=3×3×7so, LCM of 36 and 63=2×2×3×3×7=252So the required number by which 21 should be multiplied=25221=12
Regards

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