Two bodies of equal masses move with uniform velocities V & 3V respectively Find the ratio of their kinetic energies what is the amount of work done by a man pressing a rigid wall with a force of 400 newton
kinetic energy = 1/2 m v2
EK FOR IST CASE = 1/2MV2
FOR SECOND CASE = 1/2M(3V)2
RATIO= 1/2MVXV / 1/2M 9VXV = 1:9
THE WORK DONE BY THE MAN IS 0 BECAUSE SINCE THE MAN IS PUSHING THE WALL, DISPLACEMENT IS 0. SO WORK IS 0..........
PLZ. THUMBS UP!!!!!!!!!
EK FOR IST CASE = 1/2MV2
FOR SECOND CASE = 1/2M(3V)2
RATIO= 1/2MVXV / 1/2M 9VXV = 1:9
THE WORK DONE BY THE MAN IS 0 BECAUSE SINCE THE MAN IS PUSHING THE WALL, DISPLACEMENT IS 0. SO WORK IS 0..........
PLZ. THUMBS UP!!!!!!!!!