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Two boxers have to fight in a square arena of side 30m. Four poles are stuck into ground at the four corners. A rope is to be pit around the poles to keep the spectators away. What length of the rope will be required if 2m are required for tying the knots ?

Dear Student,

We are given that the two boxers fight in a square arena of side 30 metre.∴ Perimeter= 4 × side =4 × 30=120mNow, it takes 2m of rope to tie the knots and 4 knots are tied.∴ Length of rope required for tying knots = 4 × 2 = 8mThus, total length of rope required = 120 + 8 = 128m

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View Full Answer
30x4=120
2x4=8
120+8=128

Answer: 128
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of corse 128 by my eqation
 
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Can you please tell from where you have got this question? Thanks
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Please suggest..it would be very helpful
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128 is ans
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i think so 128 is the answer
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..a_(b_2a)..
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128
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30?4+2=122
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Given: 2 boxers fight in in a square arena of side 30 metre. 
Perimeter= 4 x side
               =4 x 30=120
Length for tying knot is 2 m
             = 120 x 2
              = 240 metres
 
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Oh, sorry there were 4 poles, So it is 
2 x 4= 8
120+8=128.
 
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I think so the answer is 128 because

30x4=120
2x4=8
120+8=128
Answer: 128
 
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