Two dice are thrown simultaneously. Find the probability of getting a doublet.

Total number of possible events when two dices are thrown

= 6 x 6

=36

Now total number of favorable events are (1,1);(2,2);(3,3);(4,4);(5,5) and (6,6)

So,

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6/36=1/6

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Happy to HElp!!

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thanku @gayathri...

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