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two elements x (at mass 16) and y (at mass 14) combine to form compounds a,b and c. the ratio of differebt masses of y which combines with a fixed mass of x in a,b and c is 1:3:5. if 32 parts by mass of x combines with 84 parts bymass of y in b, then in c 16 parts by mass f x willl combine with:

a) 14 parts by mass of y

b)42 parts by mss of y

c) 70 parts by mass of y

d) 84 parts by mass of y

Please find the solution to the asked query:

$InB,32partsofxcombinewithy=84parts\phantom{\rule{0ex}{0ex}}16partsofxwillcombinewithy=42parts\phantom{\rule{0ex}{0ex}}Now,thenumberofpartsofxinbothBandCisofequalmassesofywhichcombinewithafixedmassofxinBandCintheratio3:5\phantom{\rule{0ex}{0ex}}\frac{massofyinB}{massofyinC}=\frac{3}{5}\phantom{\rule{0ex}{0ex}}\frac{42parts}{massofyinC}=\frac{3}{5}\phantom{\rule{0ex}{0ex}}massofyinC=\frac{5}{3}\times 42=70parts$

Hence option C is correct.

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