Two identical parallelmplates 'A' and 'B" are connected to a battery with the switch 'S" closed. The switch is now opened and the ree space between the plates of the capacitors is filled with dielectric of dielectric constant 3. Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of dielectric.

Total electrostatic energy = 1/2* C* V2when we introduce a dielectric of constant "3", we get :C' = 3Cwhere C' is the new capacitance therefore we know that the potential across them remains the same:therefore the ratio becomes:=1/2* C* V21/2* C'* V2= C C'=C/3C=1/3

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