two masses 800kgand 600kgare of a distance 0.25m apart find the magnitude of the total force experienced by a body of mass 1kgplaced at a point distance 0.2m from 800kgand 0.15m from 600kg ???

Dear Student,
Please find below the solution to the asked query:

 
The masses are arranged at the vertices of a right angled triangle asshown in the figure above.Force between 1 kg and 600 kg:F1=Gm1m2r2=6.67×10-11×1×6000.152=1.78×10-6 NForce between 1 kg and 800 kg:F2=Gm1m2r2=6.67×10-11×1×8000.202=1.33×10-6 NNet force acting on 1 kg mass:Fnet=F12+F22=1.78×10-6 2+1.33×10-6 2=1.22×10-6 N
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