two numbers r chosen from 1,3,5.....149,151 and multiplied in all possible ways. the number of ways which will give us the product a multiple of 5 is : a 75 b 1020 c 95 d 1030  

Dear student

if total number of terms in series = nthen 151=2+(n-1)*2n=76so total terms = 76multiples of 5 are 5,15,25,...145145=2+(m-1)*10m=15remaining terms = n-m=61we get multiple of 5 if we multiply any of the m numbers with the remaining numbers=15*61=915we ger also multiple of 5, if we multiply two numbers among the 'm' numbersno of ways =C215=14*152=105total ways=915+105=1020

regards

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