Two objects A and B are dropped from a height the objects B being dropped. S after A was dropped.How long after A was dropped will A and B be 10m apart?
s = 1/2*a*t2
s1 = 1/2*10*t2
s2 = 1/2*10*(t-1)2
s1-s2 = 10m
5t2-5(t-1)2 = 10
5t2-5(t2+1-2t) = 10
5t2-5t2-5+10t = 10
10t-5 = 10
10t = 15
t = 1.5 sec
Hence Time = 1.5 sec
