Two opposite angles of a parallelogram are (3x -2)° and (50 - x)°. Find the measure of each angle of the parallelogram.

hi ahmed, 

in ||gm ABCD, suppose opposite angles A and C are (3x-2)⁰ [here ⁰ means degrees] and (50-x)⁰. Now, we know that opp. angles of ||gm are equal [NCERT theorem 8.4] .

=> 3x - 2 = 50 - x

=> 3x + x = 50 +2

=> 4x = 52

=> x = 13

if x = 13⁰  then angle A = angle C = 3x - 2 = 50 - x =37.

now, in ||gm. ABCD angle A+ angle B = 180⁰.[consecutive int. angles]

=> angle B = 143^0.  Since, angle B is equal to angle D [opp. angles are equal]

=> angle D = 143^0.

Ans:- angle A = angle C = 37 ⁰  AND angle B = angle D = 143^0.

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really brother u ROCK  :)

a lot of thanks 2 u.