Two particle A andBhaving charges 8.0x10-6C & -2.0x10-6C are held fixed with a separation of 20cm. Where should a third charged particle be placed so that it does not experience a net electric force?

Suppose the third charge is placed at P.

For the force experienced by the third at P to be zero, the net electric field at P must be zero.

From the diagram, the net field at P is,

E = k(8 × 10-6)/(0.2 + x)2 + k(-2 × 10-6)/x2

=> 0 = k(8 × 10-6)/(0.2 + x)2 + k(-2 × 10-6)/x2

=> 0 = 4/(0.2 + x)2 - 1/x2

=> 1/x2 = 4/(0.2 + x)2

=> 1/x = 2/(0.2 + x)

=> 0.2 + x = 2x

=> x = 0.2 m

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sas

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ans --5kq/a(square)

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diagonal field is directly added and remaining two will add vectorly

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