two sources of intensity I1 and I2 undergo interference in young's double split exp.show that Imax:Imin = (a1+a2)​2:(a1-a2)2  where a1 and a2 are amplitudes of disturbance for two sources s1 and s2

Dear Student,
Please find below the solution to the asked query:
Maximum amplitude during the constructive interference:Amax=a1+a2Minimum amplitude during the desstructive interference:Amin=a1-a2Intensity is square of the amplitude:I α A2Imax  α  A2maxImin  α  A2minHence,ImaxImin=a1+a22a1-a22 
Hope this information will clear your doubts about Wave optics.
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