Two wires are of the same material have masses in the ratio 3:4. What is the ratio of their extensions under the same load , if their lengths are in the ratio 9:10? a) 5/3 b] 27/30 c] 6/5 d] 27/25 Share with your friends Share 1 Sanjay Singh answered this mass of wire=area of cross section ×length×densitym1=A1×l1×ρ...(for first wire)m2=A2×l2×ρ...(for second wire)m1m2=A1×l1A2×l234=A1×9A2×10A1A2=56As youngs modulus is the same for both the wiresY=F1A1×L1∆l1...1(for first wire)Y=F2A2×L2∆l2....2(for second wire)equating 1 and 2FA1×L1∆l1=FA2×L2∆l2∆l1∆l2=A2A1×L1L2=65×910=2725regardsDear student 1 View Full Answer