# ​using mirror formula. prove that in a plane mirrori)object distance=image distanceii)image is of same size and it is virtual & erect.

Dear student
The ray diagram is shown below

From the diagram we can see that height of image is same as the height of object.
using magnification formula
$\frac{h\text{'}}{h}=\frac{-v}{-u}\phantom{\rule{0ex}{0ex}}\frac{h}{h}=\frac{v}{u}\phantom{\rule{0ex}{0ex}}v=u\phantom{\rule{0ex}{0ex}}$
This shows that the distance of object and image is same  and positive sign shows that the image is virtual and erect.
Regards

• -2
Sry i hvnt read this yet... I'll try but...
• 2
not possible..
• -3
no problem, thanks for having a look @SENITA
• 2
Thanks Everyone For Having A look To My Questions. (^.^)
• 0
What are you looking for?