Vapour density of PCl5 is 104.25 at T degree C. Then degree of dissociation of PCl5 is?
Dear Kashi Eklarkar,
PCl5 <----> PCl3 + Cl2
Initial mole 1 - -
Moles at eqm 1-x x x
Total mole at equilibrium = 1-x+x = 1+x
VD (mix) = VD (theoretical) / total mole
104.25 = 104.25 / 1+ x
1+x =1
x =1
In terms of % = 100 %
Thus its 100 % dissociation.
PCl5 <----> PCl3 + Cl2
Initial mole 1 - -
Moles at eqm 1-x x x
Total mole at equilibrium = 1-x+x = 1+x
VD (mix) = VD (theoretical) / total mole
104.25 = 104.25 / 1+ x
1+x =1
x =1
In terms of % = 100 %
Thus its 100 % dissociation.