what concentration of HCOO is present in a solution of 0.01M HCOOH ( Ka = 1.8*10^-4 ) and 0.01M HCL ?

Dear Student,

HCOOH   H+  + HCOO-  0.01             0.01         0                     initial concentration0.01-x        0.01+x     x                     equilibrium concentrationKa=[H+][HCOO-][HCOOH]or, 1.8×10-4=(0.01+x)(x)(0.01-x)or, (1.8×10-4)(0.01-x) =(0.01+x)(x)or, 1.8×10-6-1.8×10-4x=0.01x +x2or, x2+0.01x+1.8×10-4x=1.8×10-6or, x2+0.01018x = 1.8×10-6neglecting x2 as x is very smallSo, [HCOO-]=x=(1.8×10-6)(0.01018)=1.76×10-4 M

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