what concentration of HCOO is present in a solution of 0.01M HCOOH ( Ka = 1.8*10^-4 ) and 0.01M HCL ? Share with your friends Share 2 Vartika Jain answered this Dear Student, HCOOH ↔ H+ + HCOO- 0.01 0.01 0 initial concentration0.01-x 0.01+x x equilibrium concentrationKa=[H+][HCOO-][HCOOH]or, 1.8×10-4=(0.01+x)(x)(0.01-x)or, (1.8×10-4)(0.01-x) =(0.01+x)(x)or, 1.8×10-6-1.8×10-4x=0.01x +x2or, x2+0.01x+1.8×10-4x=1.8×10-6or, x2+0.01018x = 1.8×10-6neglecting x2 as x is very smallSo, [HCOO-]=x=(1.8×10-6)(0.01018)=1.76×10-4 M -13 View Full Answer Gaurang Yadav answered this ,kj -14