what does this question means .please solve me the third question in the image and give me explanation about it . Share with your friends Share 0 Ashwini Kumar answered this x=3cosecθ+4cotθ .....1y=4cosecθ-3cotθ .....2By multiplying 1 and 2, we getxy=12cosec2θ-9cosecθ cotθ+16cosecθ cotθ-12cot2θ⇒xy=12cosec2θ-cot2θ+7cosecθ cotθ⇒xy=12+7cosecθ cotθ⇒cosecθ cotθ=xy-127 .....3From 12-22, we getx2-y2=3cosecθ+4cotθ2-4cosecθ-3cotθ2⇒x2-y2=9cosec2θ+16cot2θ+24cosecθ cotθ-16cosec2θ-9cot2θ+24cosecθ cotθ⇒x2-y2=-7cosec2θ+7cot2θ+48cosecθ cotθ⇒x2-y2=-7+48cosecθ cotθ⇒x2-y2=-7+48×xy-127 From 3⇒x2-y2=-49+48xy-5767⇒7x2-y2=48xy-625 0 View Full Answer