What is the derivative of e^ax cos (bx+c) Share with your friends Share 2 Aarushi Mishra answered this Let y=eax cos bx+cdydx=d dxeax cos bx+c=eax d dxcos bx+c+cos bx+cd dxeax=eax d dxcos bx+c+cos bx+cd dxeax=eax -sin bx+cd dxbx+c+cos bx+c eaxd dxax= -eaxb sin bx+c+a eax cos bx+c -2 View Full Answer
